Introducing HMIcons
We’ve spent hundreds of hours crafting this graphics library, specifically for SCADA and industrial automation applications.
δ=PLAEdelta equals the fraction with numerator cap P cap L and denominator cap A cap E end-fraction 2. Torsion (Circular Shafts)
δ=160,00080,000,000=0.002 m or 2 mmdelta equals the fraction with numerator 160 comma 000 and denominator 80 comma 000 comma 000 end-fraction equals 0.002 m or 2 mm Practice Problem: Bending Stress A rectangular beam ( ) experiences a maximum bending moment of . Determine the maximum bending stress. Solution: Find : Find : Apply Formula: Result:
δ=(80,000)(2)(400×10-6)(200×109)delta equals the fraction with numerator open paren 80 comma 000 close paren open paren 2 close paren and denominator open paren 400 cross 10 to the negative 6 power close paren open paren 200 cross 10 to the nineth power close paren end-fraction
τ=TcJtau equals the fraction with numerator cap T c and denominator cap J end-fraction Measured in radians.
ϕ=TLGJphi equals the fraction with numerator cap T cap L and denominator cap G cap J end-fraction (Note: is the polar moment of inertia; for solid shafts). 3. Pure Bending
τ=VQIttau equals the fraction with numerator cap V cap Q and denominator cap I t end-fraction (Where is the first moment of area and is the thickness at the point of interest). Practice Problem: Axial Loading A steel rod ( ) is 2 meters long and has a cross-sectional area of . If it is subjected to a tensile load of , calculate the total elongation. Solution: Identify Givens: Apply Formula: Calculate:
Feature
Each of our 150 and counting unque graphics is delivered in five file formats, including SVG, JPG, PNG, AI, and EPS.
Your download includes our original vector design files, the pre-exported SVG files and all other common graphics formats with multiple sizes. Raster graphics are pre-exported for you at 1x, 2x and 3x sizes.
Feature
The full collection includes over 150 custom designed, unique graphics for your industrial pplication. From buttons and gauges to the hyper-specific emulsifiers and conveyor grahics, this package has you covered.
Feature
Our industrial graphics are 100% vector, and include the source files.
This enables you to easily change the size, scale and colors of your graphics.
δ=PLAEdelta equals the fraction with numerator cap P cap L and denominator cap A cap E end-fraction 2. Torsion (Circular Shafts)
δ=160,00080,000,000=0.002 m or 2 mmdelta equals the fraction with numerator 160 comma 000 and denominator 80 comma 000 comma 000 end-fraction equals 0.002 m or 2 mm Practice Problem: Bending Stress A rectangular beam ( ) experiences a maximum bending moment of . Determine the maximum bending stress. Solution: Find : Find : Apply Formula: Result: Mechanics of Materials - Formulas and Problems:...
δ=(80,000)(2)(400×10-6)(200×109)delta equals the fraction with numerator open paren 80 comma 000 close paren open paren 2 close paren and denominator open paren 400 cross 10 to the negative 6 power close paren open paren 200 cross 10 to the nineth power close paren end-fraction δ=PLAEdelta equals the fraction with numerator cap P
τ=TcJtau equals the fraction with numerator cap T c and denominator cap J end-fraction Measured in radians. Solution: Find : Find : Apply Formula: Result:
ϕ=TLGJphi equals the fraction with numerator cap T cap L and denominator cap G cap J end-fraction (Note: is the polar moment of inertia; for solid shafts). 3. Pure Bending
τ=VQIttau equals the fraction with numerator cap V cap Q and denominator cap I t end-fraction (Where is the first moment of area and is the thickness at the point of interest). Practice Problem: Axial Loading A steel rod ( ) is 2 meters long and has a cross-sectional area of . If it is subjected to a tensile load of , calculate the total elongation. Solution: Identify Givens: Apply Formula: Calculate:
